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6b^2-44b-32=0
a = 6; b = -44; c = -32;
Δ = b2-4ac
Δ = -442-4·6·(-32)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-52}{2*6}=\frac{-8}{12} =-2/3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+52}{2*6}=\frac{96}{12} =8 $
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